(2x+3)(2x^2-9x+7)=0

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Solution for (2x+3)(2x^2-9x+7)=0 equation: 


Simplifying
(2x + 3)(2x2 + -9x + 7) = 0

Reorder the terms:
(3 + 2x)(2x2 + -9x + 7) = 0

Reorder the terms:
(3 + 2x)(7 + -9x + 2x2) = 0

Multiply (3 + 2x) * (7 + -9x + 2x2)
(3(7 + -9x + 2x2) + 2x * (7 + -9x + 2x2)) = 0
((7 * 3 + -9x * 3 + 2x2 * 3) + 2x * (7 + -9x + 2x2)) = 0
((21 + -27x + 6x2) + 2x * (7 + -9x + 2x2)) = 0
(21 + -27x + 6x2 + (7 * 2x + -9x * 2x + 2x2 * 2x)) = 0
(21 + -27x + 6x2 + (14x + -18x2 + 4x3)) = 0

Reorder the terms:
(21 + -27x + 14x + 6x2 + -18x2 + 4x3) = 0

Combine like terms: -27x + 14x = -13x
(21 + -13x + 6x2 + -18x2 + 4x3) = 0

Combine like terms: 6x2 + -18x2 = -12x2
(21 + -13x + -12x2 + 4x3) = 0

Solving
21 + -13x + -12x2 + 4x3 = 0

Solving for variable 'x'.

The solution to this equation could not be determined.

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